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ycow [4]
2 years ago
10

Help me plz 10 points. its only middle school work. one question.

Mathematics
1 answer:
AnnZ [28]2 years ago
6 0

Answer:

98

Step-by-step explanation:

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Four years after opening an account that paid simple interest of 4.25% annually, a depositor withdrew the $2,380 in interest ear
satela [25.4K]

Answer:

Step-by-step explanation:

In order to figure out how much money was left in the account after the interest was withdrawn, we have to first find out how much money was initially deposited to earn that amount of interest! The means to find that initial investment is found in the simple interest formula

prt = I, where

p is the initial investement,

r is the interest rate in decimal form,

t is the time in years, and

I is the interest earned. Notice that we have all those things but the p.

Filling in:

p(.0425)(4) = 2380 and

.17p = 2380 so

p = 14000

That means that 14000 was initially invested. If the depositor withdrew the 2380, then

14000 - 2380 is the amount left in the account, namely, $11620

7 0
3 years ago
16+1008=<br><br> 56+20<br><br> please help me
kicyunya [14]
16+1008 = 1024

56+20=76
7 0
2 years ago
Read 2 more answers
Expand the bracket with distributive law <br>4(3x-4)​
USPshnik [31]
B cause vid off the things
7 0
2 years ago
PLZZZZZ NEED HELP!!!!!!
storchak [24]
Cos 18 = x/25
x = 25 cos 18
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5 0
3 years ago
write an equation of the line containing the specified point and perpendicular to indicated line. (-5,6) 4x-y=3
Radda [10]
<h2>Greetings!</h2>

Answer:

y = \frac{1}{2}x + \frac{29}{4}

Step-by-step explanation:

First, we need to rearrange the equation to make it y = mx + c

4x - y = 3

y + 3 = 4x

y = 4x -3

So the slope of the line is 4.

The slope of a line perpendicular to an equation is:

\frac{-1}{gradient}

So the slope of the perpendicular line is:

\frac{-1}{4} = -0.25

Now to find the equation of a line you can use the following equation:

y - y₁ = m(x - x₁)

Where y₁ is the y-coordinate, x₁ is the x-coordinate and m is the gradient. Plug the values in:

y₁ = 6

x₁ = -5

m = \frac{-1}{4}

y - 6 = \frac{-1}{4}(x - - 5)

To get rid of the fraction we need to multiply the whole equation by 4:

4y - 24 = -1(x - - 5)

The two negatives cancel out:

4y - 24 = -1(x + 5)

Multiply the brackets out:

4y - 24 = -x + 5

Now, to rearrange the formula back into y = mx + c

Move the -24 over to the other side making it a +24:

4y = 2x + 5 + 24

4y = 2x + 29

Divide everything by 4:

y = \frac{2}{4}x + \frac{29}{4}

y = \frac{1}{2}x + \frac{29}{4}


<h2>Hope this helps!</h2>
8 0
3 years ago
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