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Pavel [41]
3 years ago
13

Can you help me with this, please? 

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0
4x + (-3) = 8
(Hopefully)

As for the second one, I ASSUMED it would be this but I'm kinda busy and my ADHD brain just needed a break from what I was doing so just equate it for me, will you? And tell me if I was right or wrong because I have NO IDEA what I'm doing.

Let the number of days he trains for be x
So, 115x = 690
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Classify is the function as increasing decreasing or constant l
timama [110]

Answer:

Increasing

Step-by-step explanation:

Remember that f(x) is the same as y in slope intercept form y = mx + b.

We don’t have a number for “b” which means the line goes across the origin.

Since 5 replaces m, that is the slope and since it’s positive, it is increasing.

Best of Luck!

5 0
3 years ago
A straight line that is parallel to one of the sides of a given triangle intersects its other two sides (or their extensions) an
timurjin [86]

Answer:

We know that this triangle is similar because it will have all of the same angles as the first triangle. This is because two parallel lines cut by a transversal will create the same angles. In addition, they share the final angle because we are not changing that angle. Therefore, all 3 are the same, which makes them similar triangles.


6 0
4 years ago
Read 2 more answers
.
viva [34]
109 with a remainder of 6
Please give brainliest
7 0
3 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
AB=45. If RT=3(x+9), what is the value of x?
Margaret [11]
6 because 45 divides by 3 equals 15 and fifteen minus 9 equals 6, if you plug 6 into the equation it makes sense
7 0
3 years ago
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