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Naya [18.7K]
3 years ago
12

The Summer Olympics occurs every 4 years. Every 6 years a US senator runs for reelection. If both events occurred last year how

many years will pass before the US Senate seat is up reelection the same year as the Summer Olympics
Mathematics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

<u>The correct answer is 11 years</u>

Step-by-step explanation:

Summer Olympics every 4 years

US Senator runs for reelection every 6 years

Both events occurred last year

Next Summers Olympics in 3 years, 7 years, <em><u>11 years</u></em>, 15 years, 19 years, <em><u>23 years.</u></em>

Next US Senator reelection in 5 years, <em><u>11 years</u></em>, 17 years, <em><u>23 years.</u></em>

<u>The next time US Summer Olympics and the US Senate will take place the same year, will be exactly in 11 years.</u>

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when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
Which of the following fractions can be represented by a terminating decimal?
Karo-lina-s [1.5K]

Answer:

B) 13/8

Step-by-step explanation:

First we need to understand what a terminating decimal is: It is a decimal that has a finite number of decimal values that are not zero, meaning that its decimal values end at some point

Let's go through our possible answers with trial and error:

A) 8/9

8/9 = 0.888888888888...9 (Incorrect)

B) 13/8

13/8 = 1.625 (Correct)

C) 4/3

4/3 = 1.3333333333...4 (Incorrect)

D) 6/11

6/11 = 0.545454545454...54 (Incorrect

13/8 is our answer because in decimal form it is a terminating decimal.

8 0
2 years ago
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