For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
-20%
My brain is weird on how i figure it out but I divided 48 by 60 and got .80 so i just got the other whole to make it 1 so it is 20%. This is not the correct way to do this but this is how i got my answer.
Answer:
9
Step-by-step explanation:
3(h-7)+3=9
3h-21+3=9
3h-18=9
3h=9+18
3h=27
h=27/3
h=9
Please mark me as Brainliest if you're satisfied with the answer.
Answer:
Step-by-step explanation:
-8/9 is the reciprocal i believe
Answer:9/4
Step-by-step explanation:
3/4 + (1/3/1/6) - (1/2)
3/4 + (1/3 ➗ 1/6) - 1/2
3/4 + (1/3 x 6/1) - 1/2
3/4 + ((1x6)/(3x1)) - 1/2
3/4 + (6/3) - 1/2
3/4 + 2 - 1/2
(3+8-2)/4
9/4
