All categories

4 years ago

3 1/2 ÷ 3/7 = ???????????

Mathematics

2 answers:

Dafna11 [192]4 years ago

3 0

8.16666666667 that the answer

Alborosie4 years ago

3 0

In order to do this equation, I will be switching the numbers to decimals and then back to provide an answer using fractions.

3 1/2 converted to decimal form is 3.5. In order to find 3/7's value, we need to divide 3 by 7, which is ~.43 (I rounded up).

Now our equation is 3.5÷.43.

This equation would be best used on a calculator, and we have our final answer now.

Answer (rounded to the nearest hundredth): ~8.14

The ~ or tilde means "about"

Now, to convert it to fractions:

8 14/100.

Now, we use greatest common factor to simplify it the most we can

Answer: 8 7/50

NOTE: I ROUNDED SO THERE MIGHT BE A SMALL DIFFERENCE

You might be interested in

6.25% of 1200 is what number

Masja [62]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If a+bi, where b is not equal to 0, is a complex zero of a polynomial with real coefficients, then so is its _____ , a-bi.

Jobisdone [24]

Hello,

answer f: conjugate

if all coefficients are real and a+ib a zero, its conjgate a-ib is also a zero.

3 0

3 years ago

The result of 6 subtracted from a number n is at least 2. Which inequality represents this situation? A.

anygoal [31]

It had to be B

because 6 is subtracted by the number n and the only one that has n-6/ 6-n is B

3 0

4 years ago

At soccer camp, Belle spent 30 minutes practicing defense and 1 hour and 15 minutes shooting. If the camp ended at 12:15 P.M., w

SVEN [57.7K]

Answer:

10:30 A.M.

Step-by-step explanation:

12:15 P.M. -

01:15 =

11:00 A.M. -

00:30 =

10:30 A.M.

3 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago