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Readme [11.4K]
3 years ago
8

What is X in this situation? I'm thinking that you could get X, via vertical angles, but I'm not too sure.

Mathematics
1 answer:
attashe74 [19]3 years ago
4 0
Use alternate interior angles.
The angle to the left of x is 32
The angle to the right of x is 68
Since the three angles(32, x, and 68) form a straight line, they are supplementary.
32+x+68=180
100+x=180 x=80
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Multiply. Check picture.
VashaNatasha [74]

The answer is 3x^4-13x^3-x^2-11x+6.

Solution:

Use algebraic identity: a^m\times a^n=a^{m+n}

For example: x^2\times x=x^{2+1}=x^3

Given expression (x^2-5x+2) and (3x^2+2x+3).

To multiply these equations.

(x^2-5x+2)\times(3x^2+2x+3)

             =x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)

             =(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)

             =3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6

Combine like terms together.

             =3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6

             =3x^4-13x^3-x^2-11x+6

(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6

Hence the answer is 3x^4-13x^3-x^2-11x+6.

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3 years ago
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Step-by-step explanation:

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\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

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5 0
3 years ago
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