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ivolga24 [154]
3 years ago
7

Do you have to regroup to find 523-141 explain

Mathematics
2 answers:
nexus9112 [7]3 years ago
6 0
Yes you do need to regroup and the answer will be 382
Bezzdna [24]3 years ago
4 0
Yes And the answer is 382
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6z+10=-2<br><br> pls answer' <br> i willmarke brainlest
Blizzard [7]

Answer:

Step-by-step explanation: 6z=-2-10

6z= -12

z=-12/6

then z= -2

5 0
2 years ago
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3a*12 can a variable be multiplied by a constant
Virty [35]
Yes it can be multiplied
6 0
2 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
3 years ago
I need help please and thanks
lakkis [162]

Answer:

the answer is associative

Step-by-step explanation:

3 0
3 years ago
On a coordinate plane, solid circles appear at the following points: (negative 3, 2), (negative 3, 3), (1, 4), (1, negative 4),
hammer [34]

Answer:

3 points

Step-by-step explanation:

A function is a relation that maps elements of a set for the inputs (the domain, usually denoted with the variable x) into elements of another set, the set of the outputs (the range, usually denoted with the variable y).

So the relation can be represented with points (x, y), which means that point x is being mapped into point y.

Such that the needed condition is that each element of the domain is mapped into only one element in the domain.

So for example, if for a relationship we have the points (a, b) and (a, c)

The point a is being mapped into two different outputs.

Now let's go to our problem, we have the points:

(-3, 2), (-3, 3), (1, 4), (1, -4), (2, -4), (2, -2)

If we have repeated inputs, we need to remove points until we have one of each.

We can see that the inputs -3, 1, and 2 are repeated one time.

Then we need to remove one of each, for example if we remove the second, fourth and sixth points, the set becomes:

(-3, 2), (1, 4), and (2, -4)

This is a function.

Then we need to remove 3 points.

7 0
2 years ago
Read 2 more answers
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