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Burka [1]
3 years ago
13

Use the points to describe the data and determine the line of best fit.

Mathematics
2 answers:
Scilla [17]3 years ago
7 0

Answer:

Negative     1200feet     Y=-6.25x+1200

Step-by-step explanation:

creativ13 [48]3 years ago
4 0

Answer:

negative,1800 feet , y=16.25x+1,800

Step-by-step explanation:

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The table shows the percentage of students in each of three grade levels who list soccer as their favorite sport. Soccer Sophomo
Olegator [25]
The answer should be roughly 35.4%. 

You can obtain this answer by looking at the percentage of each subgrouping. For instance, 33% of the class in juniors and 45% of them list soccer as their favorites. Thus showing that 14.85% of the entire school is made up of juniors that enjoy soccer. 

If you do the totaling for all soccer lovers, you get a total of 41.95% of the school. By dividing the two numbers you get the answer above. 
4 0
3 years ago
What is the Answer to -14.5 + (-1.24)
Bingel [31]
The answer would be -15.74
4 0
3 years ago
Read 2 more answers
What is the length of a car if the length on the scale madel car is 17 cm and the scale is 2 cm : 50 cm?
Alex777 [14]

Answer:

x= 425

Step-by-step explanation:

6 0
2 years ago
Is this answer correct?​
disa [49]

Answer: ya

Step-by-step explanation:

5 0
3 years ago
If QT is 9 and TP is 8 Find the length of the following:<br><br>RP<br>RT<br>RS​
anyanavicka [17]

Answer:

i. RP = 17

ii. RT = 15

iii. RS = 30

Step-by-step explanation:

Given that; QT = 9 and TP = 8.

From the diagram, join R to P. Thus RP = QP (radius of the circle)

                        RP = QT + TP

                             = 9 + 8

                         RP = 17

Applying Pythagoras theorem to triangle TRP;

             RT = \sqrt{(RP)^{2} - (TP)^{2} }

                  = \sqrt{17^{2} - 8^{2} }

                 = \sqrt{225}

                 = 15

∴           RT = 15

But, RT = TS = 15.

So that;

       RS = 15 + 15

             = 30

        RS = 30

Therefore;  RP = 17, RT = 15 and RS = 30.

6 0
3 years ago
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