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3 years ago

A bag of trail mix weighs 1 and 1/3 lbs.How much will 2 and 1/2 bags weigh

Mathematics

1 answer:

katrin2010 [14]3 years ago

4 0

4/3 times 5/2 is 20/6, or 10/3. 3 1/3 pounds is the answer

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A local store ordered a shipment of video game systems. The store sells 30 systems weekly to customers.

xxMikexx [17]

Answer:

the correct answer is A,D,E

Step-by-step explanation:

3 0

3 years ago

(Will give Brainliest, these are angle relationships) Please help, and show work, what relationship is it and set up an equation

Vanyuwa [196]

Answer:

Supplementary, 39+5x=180, x=28.2

Step-by-step explanation:

So we know that a straight line is 180 degrees, therefore 52+(5x-13) must equal 180. This is a supplementary relationship. That's our equation, now we just have to solve.

52+5x-13=180

We can straight away combine numbers, giving us

39+5x=180

Now we subtract 39 from both sides, giving us

5x=141.

Now we will answer.

141/5=28.2=x

I'm not sure if this is right, but this is my answer :)

4 0

3 years ago

Read 2 more answers

An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,

butalik [34]

Answer:

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

$r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t$

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

$s=\sqrt{r_{A}^{2}+r_{B}^{2}}$

Rate of change of such distance can be found by the deriving the expression in terms of time:

$\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }$

Where $\frac{dr_{A}}{dt} = 500\,\frac{mi}{h}$ and $\frac{dr_{B}}{dt} = 550\,\frac{mi}{h}$ , respectively. Distances of each airliner at 2:30 PM are:

$r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi$

$r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi$

The rate of change is:

$\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }$

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

6 0

3 years ago

How many integers between 1 and 40 are multiples of 3 and 7

Elis [28]

3 goes in to 40 13 times 7 goes in to 40 5 times but it is not 13+5 because you do not want to count 21 twice

4 0

3 years ago

HELP ME PLEASE!!!!!!

Anestetic [448]

Answer:

Step-by-step explanation:

The range is 10

3 0

3 years ago