Draw a vector diagram. The net force on particle 1 = F12 + F13 + F14 These forces have to be added as vectors.
We will resolve our forces along the direction 1-4 F12 (tot) = -kQq / a^2 in the direction of particle 4 F12 = -kQq *sin (45) / a^2 F12 = -kQq /( a^2 * sqrt(2) )
By symetry this is the same as F13 F13 = -kQq /( a^2 * sqrt(2) )
F14 = -kQQ / (Sqrt(2)*a) ^ 2
For net force on particle 1 :
F12+F13+F14 = 0 -2kQq /( a^2 * sqrt(2) ) + -kQQ / (Sqrt(2)*a) ^ 2 = 0
Some simple manipulation should give you :
Q/q = -2 sqrt(2)
Answer:
C. The number of protons.
Explanation:
All atoms of mercury will remain the same while different isotopes may have different number of neutrons.
For example, mercury has 80 protons, correlating with its atomic number. However, the number of protons, neutrons, and electrons could vary between each atom. If there are 80 protons, then there has to be 80 electrons. This means that the protons have to be the same in order to apply to all atoms of mercury
4.266 m is the radius of the circular path the electron follows.
Given
Speed of electron (v) = 7.5 × 10⁶ m/s
Earth's Magnetic Field (B) = 1 × 10⁻⁵ T
We already know that
Mass of electron (m) = 9.1 × 10⁻³¹ kg
Charge on electron (q) = 1.6 × 10⁻¹⁹ C
According to the formula
Radius of circular path(r) = mass on electron × speed/ Charge × Magnetic field
Radius of circular path(r) = m × v/q × B
Put the values into the formula
r = 9.1 × 10⁻³¹ × 7.5 × 10⁶/ 1.6 × 10⁻¹⁹ × 10⁻⁵
On solving, we get
r = 4.266 m
Hence, 4.266 m is the radius of the circular path the electron follows.
Learn more about magnetic field here brainly.com/question/26257705
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Rest- to stop doing work or an activity, spend time relaxing
Motion- an act of process of moving
1. Take a breaker
2. Put a sieve on it
3. Pour the mixture and shake the sieve gently
4. Wait for the flour to fall. After the flour falls pour the rice from the sieve into other beaker then do experiment again for fair testing(optional)