The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
<h3>Force exerted outside the wheel</h3>
The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.
∑τ = 0
- Let the distance traveled by the load = 1.5 m
- Let the radius of the wheel or position of the force = 0.45 m
∑τ = R(mg) - r(F)
rF = R(mg)
0.45F = 1.5(21,200 x 9.8)
F = 6.925 x 10⁵ N.
Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
Learn more about angular momentum here: brainly.com/question/7538238
<h3><u>Answer;</u></h3>
c) created when tectonic plates converge
<h3><u>Explanation;</u></h3>
- According to the plate tectonics theory, earthquakes, volcanoes and mountain building process occur due to the interaction of the rigid plates on the earth's crust.
- <u>Mountains are as a result of volcanoes which are created by the movement of plate tectonics, which erupt and form mountains.</u> Formation of these mountains is as a result of compression of sediments caused by the collision of two convergent plate boundaries.
- It's along the convergent plate boundaries that interactions occur which creates volcanic activities and mountain building.
<span>So when the charged insulator is placed near the uncharged metallic thing they both attract each other because there will be a distribution of charge between the insulator and uncharged object. This migration of charges happens regardless of their charge positive or negative.</span>
Answer:
the ability to disolve in water is solubility
Answer:
37.18 N
Explanation:
Given:
Work (W) = 483.3 J
Distance (d) = 13 m
We can determine the value of the force as follows:
W = F.d
We replacing:
483.3 = F. 13
F = 483.3 ÷ 13
F = 37.18 N
The force on the block is 37.18 N
