Answer:
y=1/2x+1
Step-by-step explanation:
First use slope formula.
Plug in the information needed.
The slope is .
Now, use point-slope formula.
y-y1=m(x-x1)
Plug in the information needed.
y-3=1/2(x-4)
y-3=1/2x-2
y=1/2x+1
The equation of the line in slope-intercept form is y=1/2x+1.
Hope this helps!
If not, I am sorry.
Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.