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kiruha [24]
3 years ago
14

A jar contains 8 red marbles, 10 blue marbles, and 2 green marbles. If one marble is selected at random, find the probability of

selecting: Not a green marble
Mathematics
2 answers:
Arada [10]3 years ago
7 0
1/9  i THINK i'm not totally sure but ya know 
Juliette [100K]3 years ago
7 0
It should be 18/20 and simplified to 9/10!! it may not be correct though
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I'm very confused on this question and I don't know how to solve it. Any kind of help will be appreciated.
juin [17]

QP is the bisector so QPM is half NPM or

m \angle NPM = 2 m \angle QPM


6 0
3 years ago
The graph of f(x) = x2 was transformed tu
tia_tia [17]

Answer:

i: the domain.

iii: the axis of symmetry.

Step-by-step explanation:

We have the function:

f(x) = x^2

The domain of this function is the set of all real numbers, and the range is:

R: [0, ∞)

(because 0 is the minimum of x^2)

Now we have the transformation:

d(x) = f(x) + 9 = x^2 + 9

Notice that this is only a vertical translation of 9 units, then there is no horizontal movement, then the axis of symmetry does not change.

Also, in d(x) there is no value of x that makes a problem, so the domain is the set of all real numbers, then the domain does not change.

And d(x) = x^2 + 9 has the minimum at x = 0, then the minimum is:

d(0) = 0^2 + 9 = 9

Then the range is:

R: [9,  ∞)

Then the range changes.

So we can conclude that the attributes that will be the same for f(x) and d(x) are:

i: the domain.

iii: the axis of symmetry.

8 0
3 years ago
If f ( x ) = 1 3 x − 5 , what is f ( − 6 ) ?
RoseWind [281]

Answer:

-4

Step-by-step explanation:

by finding the exact value.

6 0
3 years ago
The length of a rectangle is 4x and the width of the rectangle is x^2 - 2x + 6. What is the area of the
zhannawk [14.2K]

Step-by-step explanation:

Area of rectangle(A)=l×b

=4x×(x^2-2x+6)

= 4x^3-8x^2+24x

3 0
3 years ago
The optimal operating temperature of a given car engine is within 10°F of 190°F. Write an absolute value
KiRa [710]
|x - 190|≤10

Solved: 180≤x≤200
5 0
2 years ago
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