If it has no real solutions, that means the graph does not intersect the x axis
since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up
so 'a' must be positive
if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
Answer:
402
Step-by-step explanation:
No number is shown with an underlined digit.
Only the number 402 has 2 in it that is in the units place. That digit has a value of 2.
Fill your inequality in with the y and x provided and then do the math. (4, -1) would fill in like this (I will use brackets to indicate absolute value symbols, since there are none in the equation editor):
![-1\ \textgreater \ [4]-5](https://tex.z-dn.net/?f=-1%5C%20%5Ctextgreater%20%5C%20%5B4%5D-5)
The right side is in fact equal to the left side so that's not the answer. For (-1, -4):
![-4\ \textgreater \ [-1]-5](https://tex.z-dn.net/?f=-4%5C%20%5Ctextgreater%20%5C%20%5B-1%5D-5)
and these are also equal. Let's try C now (-4, 1):
![1\ \textgreater \ [-4]-5](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%5B-4%5D-5)
. The absolute vale of -4 is 4 so 4 - 5 = -1 which is, in fact, less than 1. So C is our answer.
D. 3 and 9
(Also 12 which isn’t in the options)
3:1,3
9:1,3,9
12:1,2,3,4,6,12
Answer:
3x+9 < 60 where x = Audrey's age
Step-by-step explanation:
Lou says "even if you tripled you age", which means that if Audrey's age is represented by the variable x, then we would multiply it by 3 to get 3x. the next part says "and add 9". We already have the 3x, so we would just tack on a +9 to get 3x + 9. The last part says "you still wouldn't be as old as me." Given that 3x+9 represents Audrey's age, this equation would have to be less than Lou's age, which in this case is 60.
