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3 years ago

6

Please help me find the answer thank you

1 answer:

mario62 [17]3 years ago

5 0

Answer:

d = 1

Step-by-step explanation:

1.5 - 0.5 = 1

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And if you still have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

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In 2000 the population of a country reached 1 billion, and in 2025 it is projected to be 1.2 billion. (a) Find values for C an

Mice21 [21]

Answer:

(a) The value of C is 1.

(b) In 2010, the population would be 1.07555 billions.

(c) In 2047, the population would be 1.4 billions.

Step-by-step explanation:

(a) Here, the given function that shows the population(in billions) of the country in year x,

$P(x)=Ca^{x-2000}$

So, the population in 2000,

$P(2000)=Ca^{2000-2000}$

$=Ca^{0}$

$=C$

According to the question,

$P(2000)=1$

$\implies C=1$

(b) Similarly,

The population in 2025,

$P(2025)=Ca^{2025-2000}$

$=Ca^{25}$

$=a^{25}$ (∵ C = 1)

Again according to the question,

$P(2025)=1.2$

$a^{25}=1.2$

Taking ln both sides,

$\ln a^{25}=\ln 1.2$

$25\ln a = \ln 1.2$

$\ln a = \frac{\ln 1.2}{25}\approx 0.00729$

$a=e^{0.00729}=1.00731$

Thus, the function that shows the population in year x,

$P(x)=(1.00731)^{x-2000}$ ...... (1)

The population in 2010,

$P(2010)=(1.00731)^{2010-2000}=(1.00731)^{10}=1.07555$

Hence, the population in 2010 would be 1.07555 billions.

(c) If population P(x) = 1.4 billion,

Then, from equation (1),

$1.4=(1.00731)^{x-2000}$

$\ln 1.4=(x-2000)\ln 1.00731$

$0.33647 = (x-2000)0.00728$

$0.33647 = 0.00728x-14.56682$

$0.33647 + 14.56682 = 0.00728x$

$14.90329 = 0.00728x$

$\implies x=\frac{14.90329}{0.00728}\approx 2047$

Therefore, the country's population might reach 1.4 billion in 2047.

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2 years ago

2,000 rupees to US dollars

777dan777 [17]

Answer:

the answer is $27.18 US dollars

Step-by-step explanation: hope you found this helpful

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3 years ago

If an earthquake measures 10^4, what does it measure on the Richter scale?

devlian [24]

I think the answer is 4, the earthquake is a 4 in the scale.

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3 years ago

A class has 35 students, of which 16 are male and 19 are female. If 6 of the students are selected at random to form a committee

madreJ [45]

Answer:

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

Step-by-step explanation:

We are given that a class has 35 students

Number of male=16

Number of female=19

We have to choose 6 students for committee

We have to find the probability that exactly 2 male students are selected

Probability=P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

If we have to choose total 6 student in which 2 male and 4 female

Combination formula:

$nC_r=\frac{n!}{r!(n-r)!}$

Using the formula

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

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2 years ago

What is the unit rate in dollars for each company?

avanturin [10]

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For talk time 1.25/1/2= $2.5 for per hour

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3 years ago