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Brilliant_brown [7]
3 years ago
13

Please help with test asap

Mathematics
1 answer:
BaLLatris [955]3 years ago
7 0

Answer:

C and D

Step-by-step explanation:

180-65-55=120

this makes m<2 120 degrees and m<1 and 3 60 degrees

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Dave's gas tank holds 10 gallons. His car gets at most 25 miles per gallon. How far can he drive
ale4655 [162]

Answer:

m ≤ 250

(where m is miles)

Step-by-step explanation:

He can go a maximum of 250 miles on a tank of gas (25 miles per gallon * 10 gallons), and this can be expressed as follows:

m ≤ 250

3 0
3 years ago
How Can you divide that
Archy [21]
First you ask yourself, can 8 go into 1?  The answer is no.  Can 8 go into 12? Yes, 1 time.  So you put 1 on top of the 2 and subtract 8 from 12.  That gives you 4.  Then you pull down the 8 from 128 and ask how many times can 8 go into 48?  The answer is 6.  So your answer is 16.  Hope I helped!

6 0
3 years ago
Read 2 more answers
What is the inverse of this function? f(x)=x−7
viva [34]

Answer:

<h3> f^−1(x) = x + 7</h3>

Step-by-step explanation:

Replace f(x) with y. y = x − 7

Interchange the variables.  x = y − 7

Solve for y.  y = x + 7

Solve for y and replace with f^−1 (x).  f^−1(x) = x + 7

I hope this helps have a great day :)

4 0
2 years ago
Rashad walks 4 miles in 74 minutes. Express his rate as a simplified fraction
dem82 [27]

Answer:

2/37

Step-by-step explanation:

rate is 4/74 miles per minute, now both numerator and denominator can be divided by 2, so

4/74 = 2/37, which cannot be simplified further

4 0
3 years ago
What is the equation that represents the sequence in this problem ? Find the price after the 8th month
AVprozaik [17]

ANSWER

\begin{gathered} a_n=ar^{n\text{ - 1}} \\ a_8\text{ = \$38.26} \end{gathered}

EXPLANATION

The problem represents a geometric progression.

The general form of a geometric sequence is:

a_n=ar^{n\text{ - 1}}

where a = first term

r = common ratio

The first term from the table is the first price (for the first month). That is $80.00

To find the common ratio, we divide a term by its preceeding term.

Let us divide the price of the second month from the first.

We have:

\begin{gathered} r\text{ = }\frac{72}{80} \\ r\text{ = 0.9} \end{gathered}

The price after the 8th month is the value of a(n) when n = 8

So, we have that:

\begin{gathered} a_8\text{ = 80 }\cdot0.9^{(8\text{ - 1)}} \\ a_8\text{ = 80 }\cdot0.9^7 \\ a_8\text{ = \$38.26} \end{gathered}

5 0
1 year ago
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