A fruit company delivers
fruits
=> 3 large boxes and 2 small boxes weighs = 54 kilograms
=> 5 large boxes and 6 small boxes weighs = 108 kilograms
Now, let’s find how does each type of box weigh
=> 3a + 2b = 54, where a and b are the unknown weights of each boxes
=> 5a + 6b = 108
Multiply the first given equation by 3 on both side to cross out letter B
and find the value of A.
=> 3a(3) + 2b(3) = 54(3)
=> 9a + 6B = 162
Now subtract this by the second equation:
=> 9a + 6B = 162 – 5a + 6b =106
=> 4a = 56
=> 4a / a =56 /4
=> a = 14 – The weight of large boxes
Now, let’s find the B
=> 3(14) + 2b = 54
=> 42 + 2b = 54
=> 2b = 54 – 42
=> 2b = 12
=> 2b/2= 12/2
=> b = 6 = the weight of small boxes
Answer:
Step-by-step explanation:
Answer:
111111
Step-by-step explanation:
Digit 1: This can be any digit as all numbers are divisible by 1. I picked 1 because it was simplest.
Digit 2: The total needs to be divisible by 2, so I picked my total to be 2. I knew I already had 1 from the previous digit, so 2-1 =1 was my next digit.
Digit 3: The total must be divisible by 3, so I picked my total to be 3. I already had 2 from the two previous digits, so 3-1 = 1 was my next digit.
I hope you get the idea now, it follows the same pattern for the rest of the numbers.
Hopefully this helps, any questions let me know :)
Step-by-step explanation:
x=-2+y
7(-2+y)+2y=-5
-14+7y+2y=-5
9y=9
y=1
x=-2+1
x=-1
