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gladu [14]
2 years ago
10

FIND THE MISSING SIDE LENGTHS!!!

Mathematics
1 answer:
velikii [3]2 years ago
7 0

Answer:

Step-by-step explanation:

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What is csc ( Reduce fractional answers to lowest terms.
harina [27]

Answer:

cscA = \frac{5}{4}

Step-by-step explanation:

Using the identity

csc x = \frac{1}{sinx} , then

sinA = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{8}{10} = \frac{4}{5} , thus

cscA = \frac{1}{\frac{4}{5} } = \frac{5}{4}

4 0
3 years ago
Please help will mark brainliest
TEA [102]

we know that

total of sum of arc is 360

so, sum of both arc must be 360

so, we get

90+x=360

now, we can solve for x

90+x-90=360-90

x=270............Answer


6 0
2 years ago
Find the value of an investment of $20,000 for 12 years at an annual interest rate of 3.85%
MatroZZZ [7]

Answer:

<h2> $31,745</h2>

Step-by-step explanation:

Compound continuously:

FVn = PV x e^rn

where

PV = $20,000

r = 3.85%

n = 12 years

plugin values into the formula:

FV₁₂ = $20,000 x e ⁰°⁰³⁸⁵ ⁽¹²⁾

FV₁₂ = $31,745

3 0
3 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
How many l sounds are in the word snake
Alex

s n a ke =4 they are only 4 sound in snake when you sound it out


8 0
3 years ago
Read 2 more answers
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