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3 years ago

The table below represents the function F. The equation that represents this function is

Mathematics

2 answers:

DIA [1.3K]3 years ago

8 0

<h2>Hello!</h2>

The answer is:

C. $F(x)=2^{x}-1$

In order to find the correct option, we need to substitute/evaluate the given values of "x" into each function.

Substituting into the first equation, option A:

$F(x)=3^{x} \\F(3)=3^{3}=27\\F(3)=3^{4}=81$

... and so.

We can see that the option A is not the correct option since the obtained values do not match with the given values.

Substituting into the second equation, option B:

$F(x)=3x\\F(3)=3*3=9\\F(4)=3*4=12\\$

... and so.

We can see that the values obtained from the function do not match with the given values, so the option B is not correct.

Substituting into the third equation, option C:

$F(x)=2^{x}-1\\F(3)=2^{3}-1=8-1=7\\F(4)=2^{4}-1=16-1=15\\F(5)=2^{5}-1=32-1=31\\F(7)=2^{7}-1=128-1=127\\F(8)=2^{8}-1=256-1=255\\$

So, since all the obtained values match with the given values, we can conclude that the correct option is the option C.

Have a nice day!

UNO [17]3 years ago

4 0

Answer:

The answer is c

Step-by-step explanation:

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3 years ago

Identify the maximum value of the function y = -472 - 24x + -36.

Gnesinka [82]

Answer:

I assume that this is a quadratic equation, something like:

y = -47*x^2 - 24x + (-36)

we can rewrite it as:

y = -47x^2 - 24x - 36

Ok, this is a quadratic equation and we want to find the maximum value.

First, you can notice that the leading coefficient is negative.

This means that the arms of the graph will open downwards.

Then we can conclude that the vertex of the equation is the "higher" point, thus the maximum value will be at the vertex.

Remember that for a general function

y = a*x^2 + b*x + c

the vertex is at:

x = -b/2a

So, in our case:

y = -47x^2 - 24x - 36

The vertex will be at:

x = -(-24)/(2*-47) = -12/47

So we just need to evaluate the function in this to find the maximum value.

Remember that "evaluating" the function in x = -12/47 means that we need to change al the "x" by the number (-12/47)

y = -47*(-12/47)^2 - 24*(-12/47) - 36

y = -32.94

That is the maximum value of the function, -32.94

8 0

3 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of <em>X</em> is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago