Answer:
(x-3)(x-9)
Step-by-step explanation:
first thing you need to do is move the -6 over. so we're going to add 6 to both sides (we add because it's negative 6 and we need 0 on the right side)
so you have: x^2-12x+27
now we need to come up with two numbers that add to -12 and multiply to 27.
the factors of 27 are 9 & 3 and 27 & 1. only 9 & 3 add to 12 so we are going to use those.
since the 12 is negative however, 9 and 3 should both be negative.
therefore we get: (x-3)(x-9)
*it doesn't matter which order you put them in!
Um...weird question, but okay. Last digit would be 1.
3^104=... extremely long number, the last digit of which is 1
Consider this option:
11) 360-(95+32)=233; answer D;
14) if 2x+2=x+11, then x=9, and y-2=9+2, y=13; answer A.
Look in the table at the column that has 1 minute and 4.25 pages. Printer A prints 4.25 pages in 1 minute which is a rate of 4.25 pages per minute. The rate of printing is the slope in the equation. A rate of 4.25 pages per minute is represented by the equation y = 4.25x, where 4.25 ids the slope of the equation.
We are told that Printer A prints faster than Printer B, so Printer B must have a lower rate of printing than Printer A. The equation for Printer B must have a slope less than 4.25.
There are two choices which have a slope less than than 4.25.
Answer: y = 4.2x; y = 4x
Answer:
Step-by-step explanation:
The surface area of the square prism is obtained by using the following formula:
![A_{s} (t) = 4\cdot l(t)\cdot h(t) + 2\cdot [l(t)]^{2}](https://tex.z-dn.net/?f=A_%7Bs%7D%20%28t%29%20%3D%204%5Ccdot%20l%28t%29%5Ccdot%20h%28t%29%20%2B%202%5Ccdot%20%5Bl%28t%29%5D%5E%7B2%7D)
The rate of change of the surface area can be found by deriving the function with respect to time:
![\frac{dA_{s}}{dt} = 4\cdot [h(t)\cdot \frac{dl}{dt} + l(t)\cdot \frac{dh}{dt}] + 2\cdot l(t)\cdot \frac{dl}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdA_%7Bs%7D%7D%7Bdt%7D%20%3D%204%5Ccdot%20%5Bh%28t%29%5Ccdot%20%5Cfrac%7Bdl%7D%7Bdt%7D%20%2B%20l%28t%29%5Ccdot%20%5Cfrac%7Bdh%7D%7Bdt%7D%5D%20%2B%202%5Ccdot%20l%28t%29%5Ccdot%20%5Cfrac%7Bdl%7D%7Bdt%7D)
Known variables are summarized below:
The rate of change is:
![\frac{dA_{s}}{dt} = 4\cdot [(9\,km)\cdot (-7\,\frac{km}{min} )+(4\,km)\cdot (10\,\frac{km}{min} )] + 2\cdot (4\,km)\cdot (-7\,\frac{km}{min} )](https://tex.z-dn.net/?f=%5Cfrac%7BdA_%7Bs%7D%7D%7Bdt%7D%20%3D%204%5Ccdot%20%5B%289%5C%2Ckm%29%5Ccdot%20%28-7%5C%2C%5Cfrac%7Bkm%7D%7Bmin%7D%20%29%2B%284%5C%2Ckm%29%5Ccdot%20%2810%5C%2C%5Cfrac%7Bkm%7D%7Bmin%7D%20%29%5D%20%2B%202%5Ccdot%20%284%5C%2Ckm%29%5Ccdot%20%28-7%5C%2C%5Cfrac%7Bkm%7D%7Bmin%7D%20%29)
