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melamori03 [73]
3 years ago
14

How do I factor 1/4d-3/4

Mathematics
1 answer:
kvasek [131]3 years ago
4 0
1/4d - 3/4 =
1/4(d - 3)
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Match the like terms (picture provided)​
OverLord2011 [107]

-x ---------------- 1x

7y --------------- 12y

-12x^2 --------- 8x^2

a ----------------- -2a

6a^2------------ a^2

-5x^3 ---------- 15x^3

_____________________

you just have to match the terms which have the same power.

Hope it helps ^^

8 0
3 years ago
alexandrea and imani each think of a number. alexandras number is 8 more than Imanis number. the sum of two numbers is 50. what
juin [17]
Alexandera=a
imani=i

a is 8 more than i or
a=8+i

the sum of the 2 numbers is 50 or
a+i=50

a=8+i
so subsitute 8+i for a in a+i=50
8+i+i=50
8+2i=50
subtract 8 from both sides
2i=42
divide both sides by 2
i=21

subsiutte into a=8+i

a=8+21
a=29



a=29
i=21
3 0
3 years ago
An ice chest contains six cans of apple​ juice, eight cans of grape​ juice, four cans of orange​ juice, and two cans of mango ju
Katena32 [7]
6+8+4+2=20
2/20 to grab mango can = 1/10
8/19 (remove one for previous) fro grape juice
6/18 for apple juice = 1/3
1/10*8/19*1/3
=
8/570
=
4/285
8 0
3 years ago
You drink a beverage with 120 mg of caffeine. Each hour, the caffeine in your system decreases by about 12%. How long until you
uysha [10]

Answer:

  19.44 hours, about 19 hours 26 minutes

Step-by-step explanation:

The exponential equation that describes your caffeine level can be written as ...

  c(t) = 120·(1 -0.12)^t . . . . where t is in hours and c(t) is in mg

We want to find t for c(t) = 10, so ...

  10 = 120(0.88^t)

  10/120 = 0.88^t . . . . . . . divide by 120

  log(1/12) = t·log(0.88) . . . take logarithms

  t = log(1/12)/log(0.88) ≈ 19.4386

It will take about 19.44 hours, or 19 hours 26 minutes, for the caffeine level in your system to decrease to 10 mg.

3 0
3 years ago
Draw an array for a known 10 facts then subtract 1 from each row to find the product
Ugo [173]
So you would draw an array and then subtract 1 from each side!
hope that helped
6 0
3 years ago
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