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Nady [450]
4 years ago
11

Question 1

Mathematics
1 answer:
AveGali [126]4 years ago
8 0

Answer:

2.30/7.5

Step-by-step explanation:

4.30-2=2:30

2.5-10=7.5

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How do you solve an equation with Fractions?<br><br> Ex. 1/2(7x + 48)<br> Ex. -(1/2 x -3)+4(x + 5)
Assoli18 [71]

Its best to turn fractions into decimals so its easier to solve the problem, in order to do this you would divide the number on the top to the number on the bottom. Ex: 1 divide by 2 So the numerator divided by the denominator. The top of the faction is the numerator and the bottom of the faction is the denominator. So 1 divided by 2 = 0.5 you would replace 0.5 for the 1/2.









5 0
3 years ago
I will give brainlest please answer and explain
Artemon [7]

Answer:

c

Step-by-step explanation:

There is 6 students in the 8hr zone.

Gosh, do I have to explain?  A is a, c is c!

4+6+6+6.5+6.5+6.5+6.5+7+7+7+7+7.5+7.5+7.5+8+8+8+8+8+8.5=141.

141÷20=7.05. So, no, it is not b.

3 0
3 years ago
A ship at sea, the Gladstone, spots two other ships, the Norman and the Voyager, and measures the angle between them to be 48°.
ratelena [41]

Answer:

=3501 yards.

Step-by-step explanation:

The three ships form a triangle.  From the Voyager the angle between the Norman and the Gladstone=180-(55+48)=77°

Let the position of the Voyager be V that of Norman be N and that of the Gladstone be G

Then, the distance between Norman and voyager is g

g/sin G=v/ Sin V

4590/Sin 77=g/Sin 48

g=(4590 Sin 48)/Sin 77

=3500.8 yards

The distance between the Norman and the voyager= 3501 yards.

3 0
3 years ago
BEST ANSWER GETS BRAINLIEST!! PLEASE HELP
Makovka662 [10]
To find the mean, you add all the elements together, then divide by the number of elements. 

Like this:

(45+48+49+40+53)/5=47

in other words the correct answer is 47 inches. 

EDIT: Did the foolish mistake, of using the wrong numbers the first time. Fixed now and the answer is correct.
7 0
3 years ago
Read 2 more answers
Is it A. B. C. or D.
podryga [215]
Your answer would be b i'm pretty sure

5 0
3 years ago
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