Answer:
present value = $16750
Step-by-step explanation:
The simple interest formula allows us to calculate A, which is the final amount. According to this formula, the amount is given by A = P (1 + r*t), where P is the principal, r is the annual interest rate in decimal form, and t is the loan period expressed in years
simple interest formula:
t: time
P: present value
A: amount
r
: anual interest
A = P (1 + r*t)
P = A / (1 + r*t)
P = 19,513.75 / (1 + 3/100 * 5.5)
P = 19,513.75/ (1 + 0.165)
P = 19,513.75 / 1.165
P = 16750
present value = $16750
QUESTION 1: In these type of question, the easiest way to get the answer is try to plug in the x and y values from the options given in the equation given, So in the first question all the choice except C are more then 14 if you plug in x and y's, for eg, if you plug in x = 3 and y = 2 , you get (3+3)2 = 14 6 x 2 = 14 12 is not equal to 14, so this eliminates this choice but if you chose C you get, (11+3)1 = 14 14 = 14 so this makes C the solution for first question and for the second question do the same thing, and the answer will be D. Hope this helps
QUESTION 2: 5xy + 9 = 44
5xy = 35
xy = 7
solution pairs are:
C. (1, 7) and (7, 1)
not mentioned: (-1.-7) and (-7, -1)
Hope this helps
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Answer:
--- Standard deviation
Step-by-step explanation:
Given
See attachment for graph
Solving (a): Explain how the standard deviation is calculated.
<u>Start by calculating the mean</u>
To do this, we divide the sum of the products of grade and number of students by the total number of students;
i.e.

So, we have:



Next, calculate the variance using the following formula:

i.e subtract the mean from each dataset; take the squares; add up the squares; then divide the sum by the number of dataset
So, we have:



Lastly, take the square root of the variance to get the standard deviation


--- approximated
<em>Hence, the standard deviation is approximately 11.28</em>
Considering the calculated mean (i.e. 82.76), the standard deviation (i.e. 11.28) is small and this means that the grade of the students are close to the average grade.