Answer:
Samos
Step-by-step explanation:
Answer:
27
Step-by-step explanation:
r = 2 cm, h = 6 cm.
V = r² π h = 2² · 3.14 · 6 = 4 · 3.14 · 6 = 75.36 cm³
2000 : 75.36 = 26.54
Which question do you need answered or both?
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
Learn more about computations on:
brainly.com/question/4658834
#SPJ4
Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
I would say the answer is low, but not 100% sure.