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mihalych1998 [28]
3 years ago
12

An object travels 8 miles in 20 minutes at a constant speed. What is the

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:

The answer is 0.4mph

Step-by-step explanation:

To find the speed of an object, you do distance ÷ time.

So you do 8 ÷ 20 which is 0.4.

So the object travels 0.4mph

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3. At a bargain store, Jamal bought 2 items that each cost the same amount. Isaiah bought 3 items that each cost the same amount
coldgirl [10]

Answer:

  • $6.75 and $4.50

Step-by-step explanation:

a) <u>Jamal spent:</u>

  • 2x

<u>Isaiah spent:</u>

  • 3 (x - 2.25)

<u>The equation is:</u>

  • 2x = 3(x - 2.25)

b) <u>Solving the equation</u>

  • 2x = 3x - 6.75
  • 3x - 2x = 6.75
  • x = 6.75

c) <u>Jamal's items cost </u>

  • $6.75 each

<u>Isaiah's items cost </u>

  • $6.75 - $2.25 = $4.50 each
7 0
3 years ago
Hideki buys a skateboard that costs c dollars. After 6.5% sales tax is added, the total cost can be expressed by the expression
natulia [17]

Answer: c(1 + 0.065)

Step-by-step explanation:

3 0
3 years ago
Rounding 0.912 to the nearest hundredth
Stella [2.4K]
The answer is 0.100
5 0
3 years ago
Read 2 more answers
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
I need help with 4=2/3(2x-9
sweet [91]

Answer:

x=15/2

Hope it helps :)

4 0
3 years ago
Read 2 more answers
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