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ivanzaharov [21]
3 years ago
5

I attempted this but I was incorrect. Help?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
6 0
We need the height of the cone
what we do is we know that when height is 10, V=something, so solve for the diameter is at that point and compare it to 24, the full height
sorry if confusing

V=(1/3)hpir^2
when h=10
160pi/3=1/3(10)pir^2
ties 3 both sides
160pi=10pir^2
divide by 10pi
16=r^2
sqrt both sides
r=4

at that point, the radius is 4
the real radius of the ful is 24/2=12
4/12=1/3
it is 1/3 full

if 1/3=160pi/3cm
2/3=320pi/3cm^3

needs 320pi/3 cm^3
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Marina86 [1]

vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.

Givens

vi = 160 ft/s

vf = 0 (the rocket stops at the maximum height.)

a = - 9.81 m/s

t = ????

Remark

YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.

Equation

a = (vf - vi)/t

Solve

- 32 = (0 - 160)/t Multiply both sides by t

-32 * t = - 160 Divide by -32

t = - 160/-32

t = 5

You will also need to solve for the height to answer part B

t = 5

vi = 160 m/s

a = - 32

d = ???

d = vi*t + 1/2 a t^2

d = 160*5 + 1/2 * - 32 * 5^2

d = 800 - 400

d = 400 feet

Part B

You are at the maximum height. vi is 0 this time because you are starting to descend.

vi = 0

a = 32 m/s^2

d = 400 feet

t = ??

formula

d = vi*t + 1/2 a t^2

400 = 0 + 1/2 * 32 * t^2

400 = 16 * t^2

400/16 = t^2

t^2 = 25

t = 5 sec

The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.

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4 years ago
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Plot the axis of symmetry and the vertex for this function: h(x) = (x − 5)2 − 7.
jeka94

Answer:

The vertex and the axis of symmetry in the attached figure

Step-by-step explanation:

we know that

The equation of a vertical parabola written in vertex form is equal to

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a is the leading coefficient

(h,k) is the vertex of the parabola

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In this problem

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h(x)=(x-5)^2-7

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