Answer:
The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

92% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).
Answer:
Choice D
Step-by-step explanation:
You use the formula V=pi(radius^2)(h). Once you take the pi out and plug in the numbers, you should get V= 6^2(9). You get 324 with the pi added on after it.
Answer:
2 - 2y^2 - x/y
Step-by-step explanation:
2x^2/x^2 = 2
and
x^2/xy = x/y
therefore
2x^2/x^2 - y^2 - x^2/xy - y^2
= 2 - y^2 - x/y - y^2
= 2 - y^2 - y^2 - x/y
= 2 - 2y^2 - x/y
That's a BIG increase in price! What cost $65 yesterday is now $156. What was the increase? $156 - $65 = $91.
Next: $91 is what fraction of $65? Divide. Answer: 1.4.
Finally, multiply this last result by 100%: 140% (answer)
Answer:
6
pls mark brainlest
Step-by-step explanation: