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Gemiola [76]
3 years ago
6

Solve the system y=3x^2+3x-52x-y=3​

Mathematics
2 answers:
Elenna [48]3 years ago
8 0
Y=3x^2+3x-5. and 2x-y=3
x=-.8 so y=4.6
olya-2409 [2.1K]3 years ago
6 0
1. You can’t solve that
2. solve for x:
2x=3+y
x=3+y/2

solve for y
-y=3-2x
y=-3+2x
y=2x-3
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Complete the Square:<br> 5x^2+16x-40=8<br> (please show your steps)
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Answer:

Step-by-step explanation:

divide through by the coefficient of x^{2}

\frac{5x^{2} }{5} + \frac{16x}{5}  + \frac{-40}{5} = \frac{8}{5}

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Add half of the square of the coefficient of x  to both sides (\frac{1}{2}  X \frac{16}{5} ) ^{2}

x^{2}  + \frac{16}{5}x + (\frac{1}{2}  X \frac{16}{5} )^{2} = \frac{48}{5} +(\frac{1}{2} X \frac{16}{5} )^{2}

x^{2}  +\frac{16}{5} x +(\frac{16}{10}) ^{2} =\frac{48}{5} +\frac{64}{25}

(x +\frac{16}{10})^{2}    =\frac{304}{25}

x +\frac{16}{10} =±\sqrt{\frac{304}{25} }

x = -\frac{16}{10} ± \sqrt{\frac{304}{25} }

x=-\frac{16}{10}  + \sqrt{\frac{304}{25} } or-\frac{16}{10}  - \sqrt{\frac{304}{25} }

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