Answer:
2 is not a solution
Step-by-step explanation:
x < -12
<u>Step 1: Check if 2 is less than -12</u>
2 < -12
No, this doesn't work
Answer: 2 is not a solution
Answer:
|x - 5| = 2
Step-by-step explanation:
Since we are not given a zero on the number line, we do the following:
Average = midpoint between two numbers on the number line
For this number line,
Average = 3 + 7 ÷ 2
Average = 5
Next we find how many units away are each number from the middle:
3 is 2 units away from 5
7 is 2 units away from 5
Units away = 2
Let's use the formula:
|x - average| = Units away
Substitute values into equation
|x - 5| = 2
Now we solve
Solve for x over the integers:
|x - 5| = 2
Split the equation into two possible equations:
x - 5 = 2 or x - 5 = -2
Add 5 to both sides:
x = -5 + 5 = 2 + 5 or x - 5 + 5 = -2 + 5
Answer:
x = 7 or x = 3
LOOK AT THE GRAPH AND NUMBER LINE
<h3>
<u>Explanation</u></h3>
- Given the system of equations.

- Solve the system of equations by eliminating either x-term or y-term. We will eliminate the y-term as it is faster to solve the equation.
To eliminate the y-term, we have to multiply the negative in either the first or second equation so we can get rid of the y-term. I will multiply negative in the second equation.

There as we can get rid of the y-term by adding both equations.

Hence, the value of x is 3. But we are not finished yet because we need to find the value of y as well. Therefore, we substitute the value of x in any given equations. I will substitute the value of x in the second equation.

Hence, the value of y is 4. Therefore, we can say that when x = 3, y = 4.
- Answer Check by substituting both x and y values in both equations.
<u>First</u><u> </u><u>Equation</u>

<u>Second</u><u> </u><u>Equation</u>

Hence, both equations are true for x = 3 and y = 4. Therefore, the solution is (3,4)
<h3>
<u>Answer</u></h3>

Answer:
all it is is L*w*h
Step-by-step explanation:
how to solf A) is 5*4*10 thats it and the same for b-d
Answer: 2
Formula for cube is x^3 = 8
2^3 = 8