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3 years ago

X + 2y = 10 3x + 4y = 8 Which point is the solution to the system of equations?

Mathematics

1 answer:

bija089 [108]3 years ago

6 0

Answer:

x = -12

y = 11

Step-by-step explanation:

i used substitution and let 'x' = 10 - 2y

3(10 - 2y) + 4y = 8

30 - 6y + 4y = 8

30 -2y = 8

-2y = -22

y = 11

x + 2(11) = 10

x + 22 = 10

x = -12

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What to the tenth power can get you 300

OLEGan [10]

Answer:

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Step-by-step explanation:

Let the number we are seeking be "x", thus we can write the equation as:

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2 years ago

Determine the equation of the circle graphed below. ( please help me )

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Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

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Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

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Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

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Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

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$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

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2 years ago

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Side note: the list of possible output y values is known as the range.

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