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3 years ago

What is the value of a?

Mathematics

1 answer:

emmasim [6.3K]3 years ago

6 0

Answer:

A=8

Step-by-step explanation:

If you use the formula 30-60-90 which is a-radical 3a-2a

since the hypotenuse is 2a it equals 16

therefore if its 2a all you need to do is divide it where then you get 8.

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PLS HELP ILL GIVE BRAILIST

Rom4ik [11]

Answer:

14 hrs

Step-by-step explanation:

just keep adding up the miles till u get to 804 then u find out what half of 268 is which it is 134 then u add 804 plus 134 to get 938 then u find out how many hours that is which half 4 hours is and 2hrs

6 0

3 years ago

Pllzzzz helpppp this is and exam!!! In triangle JKL, m

Tema [17]

Answer:

x = 15

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 given angles and equate to 180

8x - 7 + x + 7 + 2x + 15 = 180 , that is

11x + 15 = 180 ( subtract 15 from both sides )

11x = 165 ( divide both sides by 11 )

x = 15

6 0

3 years ago

Draw a quick picture to find the sum or difference 2.46 + 0.78

katrin [286]

To now the difference you just have to subtract and will give you 1.68

5 0

3 years ago

Read 2 more answers

what is range of the inverse of the relation {(1, 7), (-2, 4), (5, 6), (2, 8)} A. {1, 2,5} B. {-4, 6, 7, 8} C. {1, 5} D. {-4, 7,

Rufina [12.5K]

The answer should be the domain of this relation. {-2, 1, 2, 5} but I do not see that as one of your answer choices.

The inverse of a relation is when you switch the domain and range. In other words, the domain of the original relation becomes the range of the inverse.

8 0

3 years ago

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then