1345 over 99 round to thw nearest integer

John Sells Hamburgers For $3 Each and cheeseburgers for $3.50 each. One afternoon, he sells a total of 24 burgers for $79. How M

Alexxx [7]

Let the hamburgers be x and cheese burgers be y.

x + y = 24
3x + 3.5 y = 79

x = 24 - y.

Substituting the value of x,

3( 24 - y) + 3.5 y = 79

72- 3y + 3.5 y = 79
72 + 0.5 y = 79

0.5y = 79 - 72 = 7
1/2 y = 7

thus, y = 7 * 2 = 14

Substituting the value for x,

x + y = 24
x + 14 = 24
x = 24-14 = 10
Thus, x = 10.

Thus, she sold 10 hamburgers and 14 cheeseburgers

4 0

3 years ago

To control the traffic during Ramadan month, a Police Sergeant is assigned to control the traffic

m_a_m_a [10]

To complete the table it is necessary to know the possibilities that the sergeant has to change or remain in an intersection. The probabilities (depending on the box) are:

0
0.2
0.25
0.33

<h3>How to calculate the probability of intersection change? </h3>

To know the probability of intersection change, it is necessary to locate the police officer at one of the intersections. Subsequently, count how many possibilities of change you have, for example: 3 possibilities and finally add the possibility of remaining in the intersection as shown below:

Intersection 3 has 3 possibilities of changing towards intersections 2, 8 and 4. Additionally, it has the possibility of staying at intersection 3, that is, it has 4 possible decisions.

To know the probability we divide the number 1 (because it is only a decision that we have to make) and divide it by the number of possibilities (4).

1 ÷ 4 = 0.25

According to the image we can infer that in some intersections they only have 3, 4 and 5 possibilities, so the probability of change will be different as shown below:

1 ÷ 3 = 0.33
1 ÷ 4 = 0.25
1 ÷ 5 = 0.2

Learn more about probabilities in: brainly.com/question/8069952

3 0

2 years ago

Can someone please help me with this question?!? I am so confused and I don't know how to answer it.

lbvjy [14]

9514 1404 393

Answer:

a. f(0) = 1

b. DNE (does not exist)

c. DNE

d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

f(0) = 1

f(2) does not exist. There is a "hole" in the function definition there.

__

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

__

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

__

In summary, ...

a) f(0) = 1

b) lim x → 0 does not exist

c) f(2) does not exist

d) lim x → 2 = 3

_____

<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

6 0

2 years ago

2. Check the boxes for the following sets that are closed under the given

son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...