N is M reflected across the y-axis; only the signs of the x-coordinates of M and N are different.
<u>Step-by-step explanation:</u>
In question no statements are available , below statements are the required one:
- N is M reflected across the x-axis; only the signs of the x-coordinates of M and N are different: N is reflected over y-axis not x-axis so, this option itself is wrong!
-
N is M reflected across the x-axis; only the signs of the y-coordinates of M and N are different: N-M is reflected over y-axis not x-axis , so this option is also wrong.
-
N is M reflected across the y-axis; only the signs of the x-coordinates of M and N are different: N-M are reflected over y-axis correct and sign of only x co-ordinate is changed as Co-ordinates are
and
.Hence, this statement is correct! -
N is M reflected across the y-axis; only the signs of the y-coordinates of M and N are different. N-M is reflected over y-axis , and sign of only x co-ordinate is changed not y . False statement.
We can see that point Correct statement is 3.
Answer:
-0.825
Step-by-step explanation:
Did not know the options so do not know if this is right or not.
1/5 is the answer. How to slove: You turn the mixed number into an improper fraction which would be 15/4 =, because 4(3)= 12 + 3 = 15 and the denominator stays the same so it would be 15/4. Next, multiply ( the but dont forget to "flip" the improper fraction so it's 4/15) 3/4(4/15)= 1/5
Answer: 32
Step-by-step explanation:
The output is 1/3 of the input +2