(8x+5)+(−x2−8)I don't know what to do
2 answers:
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Answer:
Step-by-step explanation:
All the terms in this polynomial are divisible by 3. Factor 3 out of this polynomial:
Now, factor inside the parentheses by grouping:
We knew to split the +2x up into -1x and 3x because -1 and 3 multiply to get -3, which is the last value in the polynomial.
Therefore, the final factored polynomial is .
Let 
. Then 
. By convention, every non-zero integer 
divides 0, so 
.
Suppose this relation holds for
, i.e. 
. We then hope to show it must also hold for 
.
You have
We assumed that, and it's clear that 
because 
is a multiple of 3. This means the remainder upon divides 
must be 0, and therefore the relation holds for . This proves the statement.
Suppose this relation holds for
You have
We assumed that