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3 years ago

3x+4y+5z+2x-2y need help please

Mathematics

2 answers:

Mademuasel [1]3 years ago

4 0

Answer:

5x + 2y + 5z

Step-by-step explanation:

Step 1: Write out expression

3x + 4y + 5z + 2x - 2y

Step 2: Combine like terms (x)

5x + 4y + 5z - 2y

Step 3: Combine like terms (y)

5x + 2y + 5z

Vlad1618 [11]3 years ago

3 0

The answer is 5x+2y+5z

That’s the answer because:
You have to combine like terms to simplify so do:
3x+2x=5x
4y+-2y=2y
5z is the only z variable
So you get
5x+2y+5z

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Let g(x)=5x-1 and h(x)=X^2-1 Solve: g(h(x))=74

AURORKA [14]

Answer:

Let's replace the h(x) function in g(x) and then use 74 as a result on the axis y. The correct answer is 4 .

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3 years ago

Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find

densk [106]

Answer:

x=4

Step-by-step explanation:

Step 1:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

$AC^2 = AB^2 + BC^2$

step 2:-

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

$(a + b)^2 = a^2 +2ab+b^2$

289 = 4x^2 +9(x^2+2x+1)

$13x^2 +18x-280 = 0$

finding factors 70 X 52 = 3640

$13x^2 +70x-52x-280 = 0$

$13x^2 -52x+ 70x-280 = 0$

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and $13x =-70$

x=4 and $x=\frac{-70}{13}$

we can not choose negative value so x value is 4

Final answer:- x = 4

verification:-

$AC^2 = AB^2 + BC^2$

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0

3 years ago

Read 2 more answers

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Answer: 204 square inches

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2 years ago

What are reasons A,B,and C in the proof?

Vlad [161]

Answer:

Option D is correct.

Explanation:

Commutative Property of Multiplication define that two numbers can be multiplied in any order.

i.e $a\times b =b \times a$

Distributive property of multiplication states that when a number is multiplied by the sum of two numbers i.e, the first number can be distributed to both of those numbers and multiplied by each of them separately.

$a \times (b+c) = a\times b+ a\times c$

Associative property of multiplication states that multiplication allows us to group factors in different ways to get the same product.

Given:

A = $( 4\times 3) + (2 \times 4 )= ( 4\times 3) + (4 \times 2 )$

B = $4 \times ( 3+2)$

C = $4 \times 5$

then;

$( 4\times 3) + (2 \times 4 )$

Using Commutative property of Multiplication we can write $2 \times 4 = 4 \times 2$ then we have;

$( 4\times 3) + (2 \times 4 ) = ( 4\times 3) + (4 \times 2 )$

Using Distributive property of multiplication;

$( 4\times 3) + (4 \times 2 ) = 4 \times ( 3+2)$

by using associative property of multiplication ,

$4 \times (3+2) = 4 \times 5$

Therefore, the reasons for A , B and C in this proof are;

A.commutative property of multiplication

B. distributive property

C. associative property of multiplication

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3 years ago

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max2010maxim [7]

Answer:

A & B are independent events. A & C, B & C are not independent events.

Step-by-step explanation:

Independent Events are the events, whose occurrences are completely unrelated to each other.

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Event C 'Red & Green dice numbers showing sum = 7' is dependent on the numbers coming on red & green dice , i.e events A & events B respectively. So, event C is dependent on both events A & B.

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