All categories

3 years ago

PLEASEEE ANSWERRRR

Mathematics

1 answer:

kvv77 [185]3 years ago

8 0

It’s -3x+6 because if you subtract three off of six it’s going to be three so that is why 3X +6 is the answer

You might be interested in

Can anyone answer 2 through 4 for me ?

Andreyy89

I know the answer for two.All you do is 9 times 3 times 2

4 0

3 years ago

How do I find the answers to the surface are of the prism.

Darya [45]

Photomath

Explanation:

3 0

3 years ago

Read 2 more answers

A circular field has a area of 14400 sq ft <br> What is the diameter of the field?

Bingel [31]

Answer:

240/sqrt(pi)

Step-by-step explanation:

We know that the area of a circle is $pi*r^2$, and we also know that the diameter of a circle is equal to $2r$.

Let's first make an equation for this problem.

pi*r^2=14400

Dividing both sides by pi, we get

r^2=14400/pi

Now, taking the square root of both sides gives us

r=120/sqrt(pi)

We are trying to find the diameter, which is twice the size of the radius.

Thus, we multiply the equation by two.

2r=240/sqrt(pi)

6 0

3 years ago

Find the volume of the region bounded above by the elliptical paraboloid zequals=9 minus 4 x squared minus 5 y squared9−4x2−5y2

Virty [35]

Answer:

$\int\limits^1_0 \int^1_0{z} \, dA$

Step-by-step explanation:

$\int\limits^1_0\int^1_0 {9-4x^2-5y^2dy} \, dx$

$\int\limits^1_0 {9y-4x^2y-\frac{5y^3}{3}|_0 ^1 } \, dx$

$\int\limits^1_0 {22/3 -4x^2} \, dx$

You finish the leftover.

7 0

3 years ago

For the following exercises, determine whether the relation is a function.

elixir [45]

Answer:

The given relation $\{(a, b),(c, d),(e, d)\}$ is a function.

Step-by-step explanation:

A relation $\{(a, b),(c, d),(e, d)\}$ is given.

It is required to determine whether the given relation is a function.

To determine whether the given function is a relation, identify the domain and range and then check whether the given relation is a function.

Step 1 of 1

The given relation is {(a, b),(c, d),(e, d)}.

The set of the first components of each ordered pair is called the domain.

From the relation, the domain is {a, c, e}.

The set of the second components of each ordered the range.

From the relation, the range is {b, d, d}.

The given relation is a function. But it is not a one-to-one function.

7 0

2 years ago