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QveST [7]
3 years ago
12

CAN SOMEONE HELP PLZ

Mathematics
2 answers:
mezya [45]3 years ago
8 0

Answe

b

no eoys tsuroeg

Alinara [238K]3 years ago
7 0

its defiantly B or A

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theresa went bowling on tuesday night. she bowled scores of 150, 165, and 165. what was her mean average score?
aleksley [76]
So, to do this, all you need to do is add up all the values, and then, with that number, divide by how many values are given.

150+165+165= 480
480/3= 160

7 0
3 years ago
Read 2 more answers
Given the quadriatic equation
vazorg [7]

Answer:

⇒  The given quadratic equation is x2−kx+9=0, comparing it with ax2+bx+c=0

∴  We get, a=1b=−k,c=9

⇒  It is given that roots are real and distinct.

∴  b2−4ac>0

⇒  (−k)2−4(1)(9)>0

⇒  k2−36>0

⇒  k2>36

⇒  k>6 or k<−6

∴  We can see values of k given in question are correct.

8 0
2 years ago
A collection of nickels and quarters is worth 2.85 . There are 3 more nickels than quarters how many nickels and quarters are th
Zolol [24]

A nickel is equal to 5 cents or 0.05 dollars.

A quarter is equal to 25 cents or 0.25 dollars.

Let number of nickels be = n

Let number of quarters be = q

0.05n+0.25q=2.85    ...........(1)

As it is given, there are 3 more nickels than quarters so equation becomes,

n=q+3   ................(2)

Plug in the value of 'n' from (2) in (1)

0.05(q+3)+0.25q=2.85

= 0.05q+0.15+0.25q=2.85

0.30q=2.70

q=9

As n=q+3 we get, n=9+3=12

Hence, there are 12 nickels and 9 quarters.

3 0
3 years ago
The slope of the line below is -3. Which of the following is the point-slope
Anna [14]

Given:

The slope of the line is -3.

The line passes through the point (2,-2).

To find:

The point-slope form of the line.

Solution:

Point slope form: If a line passes through the point (x_1,y_1) with slope m, then the point-slope form of the line is:

y-y_1=m(x-x_1)

The slope of the line is -3 and it passes through the point (2,-2). So, the point-slope form of the line is:

y-(-2)=-3(x-2)

y+2=-3(x-2)

Therefore, the required point slope form of the given line is y+2=-3(x-2).

5 0
3 years ago
The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand
Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 18.6, \sigma = 5.9

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 18.6}{5.4}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{20.4 - 18.6}{0.6768}

Z = 2.66

Z = 2.66 has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0
3 years ago
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