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QveST [7]
3 years ago
12

CAN SOMEONE HELP PLZ

Mathematics
2 answers:
mezya [45]3 years ago
8 0

Answe

b

no eoys tsuroeg

Alinara [238K]3 years ago
7 0

its defiantly B or A

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In the right triangle shown,<br> m<br> V<br> = 60° and UV = 18.<br> 60°<br> How long is UW?
frutty [35]

Answer:

Step-by-step explanation:

There are two case I used, since we are not give diagram, so I assumed that U can be the right angle and also assume that W can be the right angle so, I used both assumption to solve, check attachment

1. Using Trigonometry

Assuming that U is the right angle

Tan  θ = opp / adj

Tan 60 = UW / UV

Tan 60 = UW / 18

UW = 18 × Tan60

UW = 18 × √3

UW = 18√3

UW = 31.18 unit

Also, assume that W is right angle

Using trigonometry

Sinθ = opp / hyp

Sin60 = UW / UV

Sin60 = UW / 18

UW = 18 × sin60

UW = 18 × √3/2

UW = 9√3

UW = 15.59 unit

8 0
3 years ago
Read 2 more answers
At time t&gt;=0, the acceleration of a particle moving on the x-axis is a(t)=t+sin(t). At t=0, the velocity of the particle is -
Rufina [12.5K]

Answer:

The velocity of the particle will be zero for  t = 1.47 sec .

Step-by-step explanation:

Given equation:

                                           a(t)=t+sin(t)

lets integrate it with respect to time,

                                           ∫ a(t) dt = ∫(t+sin(t)) dt

                                      ⇒ v(t) = \frac{t^{2} }{2} - cos(t) +c

At, t=0, v= -2 so,

                                     ⇒ -2 = 0 - 1 +c

                                     ⇒ c= -1

Hence,

                                     v(t) = \frac{t^{2} }{2} - cos(t) -1

for the velocity to be zero,

                                     0 =  \frac{t^{2} }{2} - cos(t) -1

                                ⇒  t = 1.47 sec (taking only positive value)

So at 1.47 sec the velocity of particle will be zero.

7 0
3 years ago
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