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Jlenok [28]
2 years ago
6

The variable q represents a positive integer. Does 3(59 + 9) + 5q represent a number that is greater than, less than, or equal t

o 4(59 + 6)? Show your work.
Thank you if you awnser this!​
Mathematics
1 answer:
hjlf2 years ago
7 0

Answer:

Depends on the value of q.

Step-by-step explanation:

3(59+9) + 5q = 3(68) + 5q = 204 + 5q

4(59+6) = 260

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If two triangles are congruent, which of the following statements must be
Burka [1]

Answer:

[A] The corresponding sides of the triangles are congruent.

[B] The corresponding angles of the triangles are congruent.

[C] The triangles have the same size.

[D]  The triangles have the same shape.

Step-by-step explanation:

SAS which it is stands for {side, angle, side} and the meaning of SAS is that we have two triangles where we see two sides and the included angle are equal.

In Order for two triangles to be congruent must have the following below:

  1. Two figures are said to be congruent if they have same size and same shape.
  2. If two figure are congruent that means the corresponding sides will also be congruent.
  3. If two figure are congruent that means the the corresponding angles will also be congruent.

Hence, base on the given all the following are correct:

A. The corresponding sides of the triangles are congruent. √

B. The corresponding angles of the triangles are congruent. √

C. The triangles have the same size. √

D. The triangles have the same shape. √

<u><em>Kavinsky</em></u>

7 0
2 years ago
Read 2 more answers
Example of an irrational number that is less than 2 and greater than 1.5
disa [49]

For this case, the first thing you should do is take into account the irrational number definition.

An irrational number is one that can not be written as the quotient between two whole numbers.

Their number of decimals is unlimited and they are not periodic.

An irrational number within the specified domain is:

π/2 = 1.570796327    

Answer:

an example of an irrational number that is less than 2 and greater than 1.5 is:

π/2 = 1.570796327  

6 0
3 years ago
The volume of the figure
statuscvo [17]
The volume of the pyramid is 15 yd
3 0
3 years ago
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
Firlakuza [10]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

6 0
3 years ago
How many license plates can be made using 2 digits then 5 letters if repeated digits and letters are not allowed?
sveta [45]
In this question, we made a license that does not allow repeated digit and letter. That means the probability count of letter and digit will be decreased by 1 for every roll.
There is 10 kinds of digits (0-9) and 26 kinds of letters (a to z). So, 2 digits and 5 letter would be:
(10 * 9) * (26 * 25 * 24 * 23 * 22)= 710424000 kinds of license plates
3 0
3 years ago
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