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Jlenok [28]
2 years ago
6

The variable q represents a positive integer. Does 3(59 + 9) + 5q represent a number that is greater than, less than, or equal t

o 4(59 + 6)? Show your work.
Thank you if you awnser this!​
Mathematics
1 answer:
hjlf2 years ago
7 0

Answer:

Depends on the value of q.

Step-by-step explanation:

3(59+9) + 5q = 3(68) + 5q = 204 + 5q

4(59+6) = 260

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A rectangle has length 2x+3 and width 7x+9. Write a polynomial in standard form that represents the perimeter of the rectangle.
sleet_krkn [62]

Answer:

18x+21

Step-by-step explanation:

First multiply each equation by 2 since there is 2 sides for both the length and width.

2(2x+3)   2(7x+9)

4x+3         14x+18    

Then combine like terms

4x+14x       3+18

18x              21

4 0
3 years ago
a can of pinapple juice is a cylinder with a radius of 2.4 in. and a height of 11. what is the are odf the label around the can
pshichka [43]
A=2πrh+2πr²
A≈202.07
hopes that helps


8 0
2 years ago
Can someone help me pls
marysya [2.9K]

Answer its a

Step-by-step explanation:

7 0
3 years ago
Please hurry I’m being timed! (50 pts)
photoshop1234 [79]

Answer:

A

Step-by-step explanation:

An excluded value is any value of x that makes the denominator of the rational expression zero as this would make the expression undefined.

For expression A

\frac{x-3}{x^2-4}

The denominator will be zero when x² - 4 = 0

x² - 4 is a difference of squares, thus

(x - 2)(x + 2) = 0

x - 2 = 0 ⇒ x = 2

x + 2 = 0 ⇒ x = - 2

The excluded values of x are x = ± 2 ⇒ A

8 0
3 years ago
Read 2 more answers
How do i turn reapeating decimals into fractions?
inysia [295]
Easy example that shows 0.999\ldots=1:

Let x=0.999\ldots=0.\overline9.

Then 10x=9.999\ldots=9.\overline9.

So 10x-x=9.\overline9-0.\overline9, or 9x=9, and so x=1.

The basic idea is to find the period of the repeating decimal, move the n digits belonging to one period over to the left of the decimal point by multiplying by 10^n, then subtract the original repeating decimal from this new number, and finally divide by 10^n-1.

A slightly more complicated example:

Let x=0.142857142857142857\ldots=0.\overline{142857}.

Then 10^6x=142857.\overline{142857}.

Then 10^6x-x=142857.\overline{142857}-0.\overline{142857}, or

999999x=142857\implies x=\dfrac{142857}{999999}=\dfrac17
6 0
3 years ago
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