4 years ago

If 1/a, 1/b, 1/c are in Arithmetic Progress, show that 2ac/a+c.

Mathematics

1 answer:

Iteru [2.4K]4 years ago

6 0

1/b-1/a = 1/c-1/b [ since they are in arithmetic progress]
1/b+1/b = 1/c+1/a
2/b = (a+c)/ac
2ac = b(a+c)
2ac/(a+c) =b

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If 1/a, 1/b, 1/c are in Arithmetic Progress, show that 2ac/a+c.​

If 1/a, 1/b, 1/c are in Arithmetic Progress, show that 2ac/a+c.