3 years ago

If 1/a, 1/b, 1/c are in Arithmetic Progress, show that 2ac/a+c.

Mathematics

1 answer:

Iteru [2.4K]3 years ago

6 0

1/b-1/a = 1/c-1/b [ since they are in arithmetic progress]
1/b+1/b = 1/c+1/a
2/b = (a+c)/ac
2ac = b(a+c)
2ac/(a+c) =b

You might be interested in

Write two monomials whose greatest common factor is 4m

Sergeeva-Olga [200]

Stand by !
The next thing you will read in this block
will be two monomials whose greatest
common factor is 4m :

   68 x n p m q r y s
and
       124 a b g c f m t z
____________________________

And now . . .
Here are two more:

       8 m x
and
   12 k m

5 0

3 years ago

Question 6 of 10

puteri [66]

Answer:

A and C the other two are just stand alone numbers. so the answers are A and C

7 0

3 years ago

Did y’all can’t couldn’t see the other one, here is this one, NEED HELP please and thank you

docker41 [41]

Answer:

god

Step-by-step explanation:

cause god is always the answer ;)

8 0

3 years ago

How do you Divide 7÷135

lozanna [386]

By doing long division. Answer is 7/135

3 0

2 years ago

4(3x+2)−7x simplified

baherus [9]

Answer:

19x+8

Step-by-step explanation:

1) distribute the term outside the parenthesis to each term inside:

4*3x=12x

4*2=8

12x+8-7x

2) 12x+7x=19x

19x+8

Hope this helps!

7 0

3 years ago

If 1/a, 1/b, 1/c are in Arithmetic Progress, show that 2ac/a+c.​

If 1/a, 1/b, 1/c are in Arithmetic Progress, show that 2ac/a+c.