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Orlov [11]
3 years ago
11

The quotient of z and 10 increased by 32

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0

.,.,.,.,7.,.,.,.,. ,                                                                    

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NEED HELP I need to fill in the highlighted parts
Gemiola [76]

The statements and reasons why the given statements are true are presented in the following two column proofs;

Question 1

Given: 9·(x + 6) - 41 = 75

Prove \ x = \dfrac{62}{9}

Statement                   {} Reason

S1. 9·(x + 6) - 41 = 75   {}  R1. <u>Given</u>

S2. 9·(x + 6)  =  116        {}R2. <u>Addition property</u>

S3. <u>9·x + 54 = 116 </u>         {}R3. Distributive property

S4. 9·x = 62                   {}R4. <u>Subtraction property</u>

S5. x = \dfrac{62}{9}                     {} R5. <u>Division property of equality</u>

Question 2.

Statement                                     {}        Reason

S1. m∠A + m∠B = m∠D   {}                     R1.  Given

S2. ∠C and ∠D form a Linear Pair   {}   R2. Definition of linear pair

S3. ∠C and ∠D are supplementary   {}R3. <u>Linear pair ∠s are supplementary</u>

S4. <u>∠C + ∠D = 180° </u>  {}                           R4. Definition of supplementary

S5. m∠C + m∠A + m∠B = 180°   {}         R5. <u>Substitution property</u>

Question 3.

Statement                                     {} Reason

S1. ∠BDA ≅ ∠A                             {} R1. Given

S2. ∠BDA ≅ ∠CDE                      {}  R2. <u>Vertical angle theorem</u>

S3. ∠CDE ≅ ∠A                      {}       R3. Transitive property of congruency

S4. m∠CDE = m∠A                    {}   R4. <u>Definition of congruency</u>

S5. <u>(13·x + 20)° = (14·x + 15)°</u>      {}   R5. Substitution Property of Equality

S6. 14·x° = 13·x + 5°                       {}R6. <u>Subtraction property</u>

S7. x = 5                      {}                  R7. Subtraction property

Learn more here:

brainly.com/question/11331230

6 0
3 years ago
Find the qoutient 13 divided by 1649 plz for me
kumpel [21]
13/1649= 0.0078835658
7 0
3 years ago
Darla bought 0.9 kilogram of red grapes and 0.35 kilogram of green grapes.
madam [21]

keep trying good luck to you

3 0
3 years ago
What is the midpoint of the segment below?
In-s [12.5K]

Answer:

Your answer is A.(7,3)

7 0
3 years ago
Find a cubic polynomial with integer coefficients that has $\sqrt[3]{2} + \sqrt[3]{4}$ as a root.
Paul [167]

Find the powers a=\sqrt{2}+\sqrt{3}

$a^{2}=5+2 \sqrt{6}$

$a^{3}=11 \sqrt{2}+9 \sqrt{3}$

The cubic term gives us a clue, we can use a linear combination to eliminate the root 3 term $a^{3}-9 a=2 \sqrt{2}$ Square $\left(a^{3}-9 a\right)^{2}=8$ which gives one solution. Expand we have $a^{6}-18 a^{4}-81 a^{2}=8$ Hence the polynomial $x^{6}-18 x^{4}-81 x^{2}-8$ will have a as a solution.

Note this is not the simplest solution as $x^{6}-18 x^{4}-81 x^{2}-8=\left(x^{2}-8\right)\left(x^{4}-10 x^{2}+1\right)$

so fits with the other answers.

3 0
3 years ago
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