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Luden [163]
3 years ago
6

The diagonal of the rectangle is 13 inches, and the side lengths of the triangles are Pythagorean triples. To the nearest tenth,

what is the area of the shaded part of the figure?
Mathematics
1 answer:
frosja888 [35]3 years ago
3 0
1) A Pythagorean triples is a set of three integers, a, b, c,  that follow the rule a^2 + b^2 = c^2

2) Assumin c is the diagonal of your rectangle and the hypotenuse of the triangles, you are looking this:

13^2 = a^2 + b^2

=> 169 = a^2 + b^2

Two integer numbers that meet that equality are 5 and 12:

5^2 = 25
12^2 = 144
=> 5^2 + 12^2 = 25 + 144 = 169

 => 13^2 = 5^2 + 12^2

Now that you have the three numbers you know the dimensions of the figure and can calculate the area of the shaded part. I cannot do that for you becasue you did not include the figure.
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Answer:

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Darlene bought 3.4 yards more

Step-by-step explanation:

Darlene = 7 yards + 20% extra

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= 7 + (0.2 × 7)

= 7 + 1.4

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Chris = 4 yards + 25% of 4 yards

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= 4 + (25% × 4)

= 4 + (0.25 × 4)

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Darlene bought more fabric

How much more?

Darlene - Chris

= 8.4 yards - 5 yards

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Answer:

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An isosceles triangle ABC has legs of length 24 and a vertex angle that measures 36º . Determine the length of its base, BC , to
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Answer: BC=14.8

Step-by-step explanation:

By definition, an Isosceles triangle has two equal sides and its opposite angles are congruent.

Observe the figure attached, where the isosceles triangle is divided into two equal right triangles.

So, in this case you need to use the following Trigonometric Identity:

sin\alpha =\frac{opposite}{hypotenuse}

In this case, you can identify that:

\alpha =\angle BAD=\angle CAD=18\°\\\\opposite=BD=CD=x\\\\hypotenuse=AB=AC=24

Substituting values, and solving for "x", you get:

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Therefore, the length of BC rounded to nearest tenth, is:

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