1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luden [163]
3 years ago
6

The diagonal of the rectangle is 13 inches, and the side lengths of the triangles are Pythagorean triples. To the nearest tenth,

what is the area of the shaded part of the figure?
Mathematics
1 answer:
frosja888 [35]3 years ago
3 0
1) A Pythagorean triples is a set of three integers, a, b, c,  that follow the rule a^2 + b^2 = c^2

2) Assumin c is the diagonal of your rectangle and the hypotenuse of the triangles, you are looking this:

13^2 = a^2 + b^2

=> 169 = a^2 + b^2

Two integer numbers that meet that equality are 5 and 12:

5^2 = 25
12^2 = 144
=> 5^2 + 12^2 = 25 + 144 = 169

 => 13^2 = 5^2 + 12^2

Now that you have the three numbers you know the dimensions of the figure and can calculate the area of the shaded part. I cannot do that for you becasue you did not include the figure.
You might be interested in
-1/2 divided by X=7/3
marshall27 [118]
The exact form is x= -3/14
7 0
3 years ago
I feel 12 less than 4 times a number is 8, the number is 5. Write a different sentence where the unknown number is also 5.
Lyrx [107]

9 less than 3 times a number is 6

8 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
Is 290 10 times as much as 2,900
ale4655 [162]
Yes if you were to so 290 times 10 on a calculator or 2,900 divided by 10
6 0
3 years ago
Read 2 more answers
a man has 25 coins in his pocket all of which are dimes and quarters. if the total value of his change is 430 cents, how many di
valentinak56 [21]

Answer:16 quarters and 3 dimes

Step-by-step explanation:

430/25 (Quarters) = 17

25x16

(Because you can’t have 17 since 25x17=425 leaving no room for dimes.)

=400

Now 430-400=30

30 more cent is needed,

30/10(Dime value)

Is 3, so the answer is the man has 16 quarters and 3 dimes

7 0
3 years ago
Other questions:
  • Which of the following equations is of a parabola with a vertex at (0, 3)?
    10·2 answers
  • Solue for n<br> (M+n)/p=r
    14·1 answer
  • Jane paid a total of $79 for a pair of shoes and 2 hats.The price of each hat was $12.Use rounding toestimate how much Jane paid
    8·1 answer
  • What is the median of the scores in this stem-and-leaf plot?
    11·1 answer
  • (5 + x) + (5 + x + 2)=
    12·2 answers
  • If I put 1500 into my savings account and earned $180.00 of interest at 4% simple interest, how long was my money in the bank?
    8·1 answer
  • What is the image of Q for a dilation with the center (0,0) and a scale factor of 0.5?
    8·1 answer
  • PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG.
    15·2 answers
  • First 6 multiples of 4: 4, 8, 12, 16, 20, 24 First 6 multiples of 6: 6, 12, 18, 24, 30, 36 What is the least common multiple (LC
    11·1 answer
  • Please answer this math problem sceenshot below
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!