All categories

3 years ago

7-8÷4(3^2-1) ~answer step by step please~

Mathematics

1 answer:

Schach [20]3 years ago

5 0

Answer:

-9

Step-by-step explanation:

Simplify the following:

7 - 8/4 (3^2 - 1)

Hint: | Evaluate 3^2.

3^2 = 9:

7 - 8/4 (9 - 1)

Hint: | Subtract 1 from 9.

9 - 1 = 8:

7 - 2×8

Hint: | Divide 8 by 4.

8/4 = (4×2)/4 = 2:

7 - 2×8

Hint: | Multiply -2 and 8 together.

-2×8 = -16:

7 + -16

Hint: | Subtract 16 from 7.

7 - 16 = -9:

Answer: -9

You might be interested in

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

2 years ago

Read 2 more answers

Quadrilateral A'B'C'D' is a reflection of Quadrilateral ABCD over the y-axis What is the length of C'D'

MArishka [77]

Answer:

C'D' = 4

Step-by-step explanation:

When the figure is reflected, the length of the segments does not change.

CD = 4 so C'D' = 4

4 0

2 years ago

Read 2 more answers

Answer now pls I’ll give you brainliest just pls answer

hjlf

Answer:

7,460 (or 7460 as some non-native English speakers would write it) since you always round a number down when it ends in 1 through 4, and always round it up when it ends in 5 through 9.

Step-by-step explanation:

pls give me brainliest plssssssssssssssssssssss.

5 0

2 years ago

Read 2 more answers

What is the unknown factor 9Xp= 45

Airida [17]

5 is your missing factor because 9*5=45 btw dont use x for multiplication use this *

3 0

2 years ago

1.4(0.5x+4.2y)−3.5(0.2x−1.5y)<br> simplify<br> lots of points

Vilka [71]

1,4(0,5x + 4,2y) - 3,5(0,2x - 1,5y)

1,4.0,5x + 1,4.4,2y - 3,5.0,2x + 3,5.1,5y

0,7x + 5,88y - 0,7x + 5,25y

0,7x - 0,7x + 5,88y + 5,25y

11,13y

7 0

3 years ago