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tester [92]
2 years ago
14

Part a give the number of total electron groups, the number of bonding groups, and the number of lone pairs for the geometry dep

icted in (a). express your answers as integers separated by commas.

Mathematics
1 answer:
VLD [36.1K]2 years ago
6 0
The photo is attached so you could understand the total electron groups, the number of bonding and lone pairs.

A. There are 4 electron groups, 4 bonding groups, 0 lone pairs 

<span>B.There are 5 electron groups, 3 bonding groups, 2 lone pairs </span>
<span>
C. There are 6 electron groups, 5 bonding groups, 1 lone pair</span>

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The area if a rectangle is 53.6cm^2.If the length is multiplied by four and the width is halved, the area would then be?
e-lub [12.9K]

Answer:

26.8cm²

Step-by-step explanation:

the area if a rectangle is 53.6cm^2.If the length is multiplied by four and the width is halved, the area would then be?​

Area of rectangle = length x width

53.6 = 4L x 1/2 W

53.6 = 2L × W

Divide both sides by 2

L × W = 53.6 ÷ 2

New area  = 26.8cm²

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3 years ago
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artcher [175]

Answer:

1 / 8², B

Step-by-step explanation:

8 / 8³

8³ = 8*8*8

So, the equation can also be written as:

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divide the numerator and denominator by 8.

1 / 8*8

This is equal to:

1 / 8²

The answer is B.

7 0
2 years ago
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jonny [76]

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Jobisdone [24]

Answer:

C

Step-by-step explanation:

The circumference (C) of a circle = 2πr ← r is the radius

Given C = 15π the equating gives

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r = \frac{15}{2} = 7.5 cm

The area (A) of a circle is calculated using the formula

A = πr² = π × 7.5² = 56.25π cm² → C

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