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tester [92]
3 years ago
14

Part a give the number of total electron groups, the number of bonding groups, and the number of lone pairs for the geometry dep

icted in (a). express your answers as integers separated by commas.

Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0
The photo is attached so you could understand the total electron groups, the number of bonding and lone pairs.

A. There are 4 electron groups, 4 bonding groups, 0 lone pairs 

<span>B.There are 5 electron groups, 3 bonding groups, 2 lone pairs </span>
<span>
C. There are 6 electron groups, 5 bonding groups, 1 lone pair</span>

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Please answer asap!! Thanks! :)
kherson [118]

Answer:

18

Step-by-step explanation:

Let the two numbers be x and y

x+y = 9

x-y = 3

Add the two equations together

x+y = 9

x-y = 3

------------------

2x = 12

Divide by 2

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4 years ago
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Ilia_Sergeevich [38]

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14.95+14.95=29.90

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3 years ago
Describe and correct the error(s) made in each of the problems below.
ladessa [460]

Answer:

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

  • When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
  • When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
  • Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

1-x / (5-x)(-x)=x-1 / x(x-5)

Let's arrange into format:

\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

Now for the second expression

5/s+2/5=2/s

Let's arrange into format

\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

6 0
3 years ago
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