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ololo11 [35]
3 years ago
14

Why is human blood type an example of multiple alleles? codominance?

Biology
2 answers:
Yanka [14]3 years ago
8 0
It is because when alleles show a co-dominant relationship , neither allele is dominant and both are expressed in the phenotype of the heterozygote. The human ABO blood groups provide a good example of codominace. The ABO system is due to a gene that codes for molecules on the surface of red blood cells
Katyanochek1 [597]3 years ago
6 0
When alleles show a co-dominant relationship neither alleles is dominant and both are expressed in the phenotype of the heterozygote. The human body ABO blood groups provide a good example of codominance, The ABO system is due to a gene that codes of molecules on the surface of red blood cells. 
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Find the hypotenuse of a right triangle whose legs both have a length of 5.
natali 33 [55]

Answer:

Hypotenuse = 7.07 units.

Explanation:

The sides of the right angle triangle are the opposite and adjacent side; which are both equal in this case.

Given the following data;

Opposite = 5 units

Adjacent = 5 units

To find the hypotenuse, we would use the Pythagorean theorem given by the formula;

Hypotenuse² = opposite² + adjacent²

Hypotenuse² = 5² + 5²

Hypotenuse² = 25 + 25

Hypotenuse² = 50

Hypotenuse = √50

Taking the square root of both sides, we have;

Hypotenuse = 7.07 units.

7 0
3 years ago
In a population of pea plants, 36 plants are homozygous for the dominant trait of yellow peas (YY), 48 plants are heterozygous f
baherus [9]

Answer:

The correct answer would be C. 0.60

It can be calculated with the help of Hardy-Weinberg equation i.e

p² + q² + 2pq = 1

Also, p + q = 1

  • where p represents the frequency of dominant allele.
  • q represents the frequency of recessive allele.
  • p² represents the frequency of homozygous dominant genotype .
  • q² represents the frequency of homozygous recessive genotype .
  • 2pq represents the frequency of heterozygous genotype.

Number of homozygous dominant (YY) = 36

Number of homozygous recessive (yy) = 16

Number of heterozygous dominant (Yy) = 48

Total number of plants = 100

Now, frequency of homozygous dominant (YY) = 36/100 = 0.36

Therefore, p² = 0.36

So, p = √0.36 = 0.60

Hence, frequency of dominant allele (Y) = 0.60

5 0
3 years ago
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