If a couple plans to have 6 children, what is the probability that there will be at least one boy? Assume boys and girls are e
1 answer:
Answer:
a)
b) The probability for the couple to be very confident that they will get at least one boy in 6 children is %
Step-by-step explanation:
The probability of having a boy or girl is
A couple plans to have 6 children
Probability of having at least one male child
On solving the above term, we get -
The probability for the couple to be very confident that they will get at least one boy in 6 children is
Thus, the probability is very high
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Answer:
x = ± - 3
Explanation:
I'm assuming you want the solutions to that equation, so here goes! (If not, please comment.)
(x-3)(x+9)=27
Let's FOIL this all out and expand. (Remember: First, Outer, Inner, Last.)
x^2 + 9x - 3x - 27
(first+ inner + outer + last)
x^2 + 9x - 3x - 27 = 27
Combine like terms, and add 27 to both sides.
x^2 + 6x - 27 + 27 = 27 + 27
x^2 + 6x = 54
Let's complete the square, because factoring doesn't work, and because it's good practice.
x^2 + 6x + ___ = 54 + ____
In the blank we will put b/2 ^2 = 6/2 ^2 = 3^2 = 9 to complete the square.
x^2 + 6x + 9 = 54 + 9
Now we've got a perfect square factor:
(x + 3)^2 = 63
sqrt(x+3)^2 =
x + 3 = ±
x = ± - 3
We have been given a system of equations. and
. We are asked to find the solution of our given system of equations.
The solution of our given system of equations will be the point, where both lines will intersect.
To find intersection point, we will equate both equations as:
Now we will substitute in equation
and solve for y.
Therefore, the point is the solution of our given system of equations.
We can verify our answer by graphing both equations.
