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Verizon [17]
3 years ago
8

Calculate the sum of the infinite series 72+60+50+125/3+...

Mathematics
1 answer:
erica [24]3 years ago
5 0

Answer:

223.666666667

This took a while lol

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D is the midpoint of CE. If CD= 2x+10 and DE =3x-18, find x and CE<br><br> x=<br> CE=
Veseljchak [2.6K]

Answer:

<h2>x = 28</h2><h2>CE = 132</h2><h2 />

Step-by-step explanation:

|<------------- CE -------------------->|

C-------------------D-------------------E

       2x + 10              3x - 18

2x + 10 = 3x - 18

2x - 3x = -18 - 10

-x = -28

x = 28

CE = 2x + 10 + 3x - 18

CE = 2(28) + 10 + 3(28) - 18

CE = 56 + 10 + 84 - 18

CE = 132

3 0
3 years ago
ACORDING OT THE IMAGE, WHATS THE ANSWER???? <br><br><br><br><br> HURRY 30 POINTS BRAINLIEST!!!
ELEN [110]

Answer:

231 cubed centimeters

Step-by-step explanation:

Find the area of the base of the pyramid

18 x 7=126 divided by 2= 63 cm

Next, make sure to the remember the formula is V=\frac{1}{3} BH

1/3(63)(11)=

21(11)=231

231 cubed centimeters is the answer.

8 0
3 years ago
Read 2 more answers
The perimeter of a stop sign is 99.2 inches. Each side of the stop sign is equal.
san4es73 [151]

Answer: The equation can be written as 8n = 99.2.

Step-by-step explanation:

In my answer, I used the variable n to distinguish itself as one side of the stop sign. 99.2 is the final perimeter in inches.

A stop sign is an octagonal shape (otherwise, it is made up of 8 equal sides). Therefore, with this information, you can interpret that the length of one side would be equal to the length of all of the other sides.

Hence, the answer can be represented as 8n = 99.2.

6 0
3 years ago
Quadrilateral ABCD has vertices A(1,0) B(5,0) C (7,2) D(3,2). Use slope to prove that ABCD is a parallelogram.
Galina-37 [17]

Answer:

AD \parallel BC

AB \parallel CD

Step-by-step explanation:

The vertices of quadrilateral ABCD are A(1,0) B(5,0) C (7,2) D(3,2).

The slope of side AB is

M_{AB}=\frac{0-0}{5-1} =\frac{0}{4}=0

The slope of side BC is

M_{BC}=\frac{2-0}{7-5} =\frac{2}{2}=1

The slope of side CD is

M_{CD}=\frac{2-2}{3-7} =\frac{0}{-4}=0

The slope of AD is

M_{AD}=\frac{2-0}{3-1} =\frac{2}{2}=1

AD \parallel BC

AB \parallel CD

We see that the opposite sides of the quadrilateral ABCD are equal.

Hence the quadrilateral is a parallelogram

4 0
3 years ago
I dont understand this help me :( What is the equation of a line with a slope of ​3​ and a point (3, 1) on the line?
spayn [35]

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{1})~\hspace{10em} slope = m\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-1=3(x-3) \\\\\\ y-1=3x-9\implies y=3x-8

7 0
3 years ago
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