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Lynna [10]
3 years ago
15

Solve 3x2 18x 15 = 0 by completing the square.

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0
3(x^2 + 6x + 5) = 0
3(x^2 + 6x + 9 + 5 - 9) = 0
3(x + 3)^2 + 3(-4) = 0
3(x + 3)^2 - 12 = 0
3(x + 3)^2 = 12
(x + 3)^2 = 4
x + 3 = sqrt(4)
x = -3 + or - 2
x = -3 + 2 or -3 - 2
x = -1 or -5
The correct answer option is option c.
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Step-by-step explanation:

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ICE Princess25 [194]

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:

(-15,-10).

<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>

It is given by the derivative at x = x0, that is:

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In this problem, the function is:

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f^{\prime}(x) = 0.4x + 5

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