Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is

, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 =
8.88 mg.</span>
Answer:
Step-by-step explanation:
Area = length * width
length: x + 3
width: x - 5
A = (x + 3)(x - 5)
Simplify (x + 3)(x - 5) using the FOIL method:
1. First numbers: multiply the first number of each binomial together--x*x = x%5E2
2. Outer numbers: multiply the outer number of each binomial (out of the entire expression, the number farthest to the left (x) and the number farthest to the right (-5))--x*-5 = -5x
3. Inner numbers: multiply the inner number of each binomial--3*x = 3x
4. Last numbers: multiply the last number of each binomial--3*-5 = -15
==> Now, add all of the results together and combine like terms: x%5E2+-+5x+%2B+3x+-+15 = x%5E2+-+2x+-+15
Therefore, A = x%5E2+-+2x+-+15
Answer:
Step-by-step explanation:
12.8 feet
The time when the maximum serum concentration is reached is obtained by equating the derivative of C(t) to 0.
i.e. dC(t)/dt = 0.06 - 2(0.0002t) = 0.06 - 0.0004t = 0
0.0004t = 0.06
t = 0.06/0.0004 = 150
Therefore, the maximum serum concentration is reached at t = 150 mins
The maximum concentration = 0.06(150) - 0.0002(150)^2 = 9 - 0.0002(22,500) = 9 - 4.5 = 4.5
Therefore, the maximum concentration is 4.5mg/L