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2 years ago

What is the equation for the line in slope-intercept form?

Mathematics

2 answers:

masha68 [24]2 years ago

5 0

Answer:

y=mx+b is slope-intercept form

where m is the slope and b is the y intercept.

Since the line crosses the y axis at 0,0 the intercept is +0 or just nothing.

now all we need to do is find the slope

to do that just go from the y intercept (the first point) y units up and x units over untill u cross at the next point. for examples from (0, 0) to (1, 8)-the next point- i need to go up 8 units up and 1 unit over. this is described as rise over run and that is your slope 8/1 rise/run. rise is how many units i go up (or down) from the y intercept until the next point that lies on the line and run is how far i need to go over from how many units i just went up. If u continue to go 8 up and 1 over from each point u will see that u get a point lying of the line. This is why 8/1 is your slope

8/1 is the slope and 0,0 is your y intercept so we put nothing

the equation is y=8x

Step-by-step explanation:

stiv31 [10]2 years ago

4 0

Answer:

y=8x

Step-by-step explanation:

Pick two points (0,0) (2,16)

Then 16-0/2-0= 8

8 is the slope

The y intercept is 0 so

y=8x

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6(4x + 5) = 3(x + 8) + 3
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2 years ago

Please could you explain this step by step I’m really stuck.

allochka39001 [22]

Answer:

x = -2.5
x = 2

Step-by-step explanation:

Hello!

We can remove the denominators by multiplying everything by it.

Solve:

$\frac{5}{x + 3} + \frac4{x + 2} = 2$
$5 + \frac{4(x + 3)}{x + 2} = 2(x + 3)$
$5 + \frac{4x + 12}{x + 2} = 2x + 6$
$5(x + 2) +4x + 12 = (2x + 6)(x + 2)$
$5x + 10 + 4x + 12 = 2x^2 + 6x + 4x + 12$
$9x + 22 = 2x^2 + 10x + 12$

Let's make one side equal to 0.

$0 = 2x^2 + x - 10$

Solve by factoring, and then the zero product property.

$0 = 2x^2 + x - 10\\$

Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, $ax^2 + bx + c$ , think two numbers that equal "ac" and add up to "b".