3 years ago

Find the value(s) of x that make the equation true.

1 answer:

6 0

$4 {x}^{2} + 6x + 2 = 0 \\ 2(2 {x}^{2} + 3x + 1) = 0 \\ 2(2x + 1)(x + 1) = 0 \\ x = - \frac{1}{2} \: or \: x = - 1$
Hope this helps. - M

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